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1.5x^2-x=4
We move all terms to the left:
1.5x^2-x-(4)=0
We add all the numbers together, and all the variables
1.5x^2-1x-4=0
a = 1.5; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·1.5·(-4)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2*1.5}=\frac{-4}{3} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2*1.5}=\frac{6}{3} =2 $
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